Take the number 192 and multiply it by each of 1, 2, and 3:
By concatenating each product we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of 192 and (1,2,3)
The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1,2,3,4,5).
What is the largest 1 to 9 pandigital 9-digit number that can be formed as the concatenated product of an integer with (1,2, ... , ) where ?
Runtime: 0
Average: 0 Runs: 0
SD: 0 ms
Max: 0
Min: 1000
My insight was that the "seed" number had to start with a 9 and that the maximum "seed" had to be 4 digits since a 5-digit number would always produce a 10-digit number on its second iteration. I used a little ﾶﾑｲん-ﾌuｲ丂u to append the 9 and then I cycled through a for loop 998 times. 61,501